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Why does the equation P = F^[1/(1-F)] approach 1/e as F approaches 1?

While reviewing asymptotic analysis in a research context, I encountered this expression. Its convergence to 1/e seems elegant yet non-obvious. As someone working with mathematical models in engineering, I’m keen to grasp not just the formal proof but the underlying intuition why the natural base e emerges here, and how this limit might appear in applied settings like statistical mechanics or optimization.

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By Shobha Answered 1 year ago

This limit often appears in contexts like reliability engineering or statistical models where a parameter approaches a boundary. I’ve found it helpful to set x = 1−F, so as F→1, x→0. Then the expression becomes (1−x)^(1/x), which is a classic form recalling the definition of e. Specifically, (1−x)^(1/x) → e^(−1) = 1/e as x→0. Intuitively, you’re seeing how a process balancing growth and decay naturally converges to the exponential constant. In practice, I’ve seen similar limits arise in queuing theory and failure-rate models, where e elegantly captures asymptotic stability.

   

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